Ethan buys a new phone. It cost 75$. He will pay for this on his 1st bill. His phone plan charges 0.06 dollars per minute on the phone.
'He has $90 to spend on his 1st bill. How long can he be on his phone to not go over his budget?

250 minutes

Step-by-step explanation:

90-75=15

15/0.06=250

x = 250 minutes

Step-by-step explanation:

The equation for this problem can be set up as follows-

Y = 0.06x+75

y = total phone bill

x= number of minutes on his phone

If Ethan can spend a total of $90 maximum, then y = 90

90 = 0.06x +75 solve for X to determine how many minutes he can be on his phone to reach a $90 total.

x = 250 minutes

the answer is 62

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2