Log x √x + log √c c² = ?
please help me?;

Given that

log √x (x) + log c² (c)

⇛ log x^1/2 (x) + log c² (c)

We know that

log a^m (b^n) = m/n log a (b)

⇛ 1/2 log x (x) + 2 log c (c)

We know that

log a ( a) = 1

⇛ (1/2)(1) + 2(1)

⇛ (1/2)+2

⇛ (1+4)/2

⇛ 5/2

Answer:- log √x (x) + log c² (c) = 5/2

[(x) ,(c) , (a) represents the bases ]

Additional comment:

also read similar questions: if log^2(x)=log^2(a)+log^2(b)-log^2(c) then x is....

simplify the following expression. log(x2) - log(x) A. log(x^2+x) B. log(x^3) C. log(x^2-x) D. log(x)....

a

step-by-step explanation:

when a number is between two straight lines it means the absolute value.

to find absolute value you need to know how many numbers is that number away from 0.

when finding absolute value the number will always come out positive

so absolute value of -3 is 3

absolute value of 3/2 is 3/2

absolute value of -2 is 2

absolute value of 3.5 is 3.5

absolute value of -1 is 1

now put these numbers in order:

a)   |-1|, |3/2|, |-2|, |-3|, |3.5|