How much water should be added to 5 gallons of 50% acid solution to get a 20% solution?

3 gallons

Explanation:

So we know that we're adding pure acid, so that would be 100%. We don't know how much pure acid we're adding, so we'll designate  x  to represent that quantity. Forming the equation, we get 1.00x + 0.2(5) = 0.5(x+5)

So we need 3 gallons of pure acid.

7.5 gallons

Step-by-step explanation:

2.5/5+x=0.2

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

a

step-by-step explanation: