Given m∠2 = 72°, m∠1 = 2 · m∠3, and ∠4 ≅ ∠ 8, find m∠1, m∠3, m∠4, m∠5, m∠6, m∠7, and m∠8.

Idon't see any graph, however the graph of the function : f(x) = x²-2x+3 is a parabola: 1) open upward (since a> 0)2) it intersects y-axis in 3 (y=3)3) its axis of symmetry is x = +1 ( -b/2a)4) it's minimum is y = -2, so its vertex is (1,-2)5) it doesn't intersect the x-axis since discriminant < 0 

Where exactly is the graph? mind taking a picture of it?