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Mathematics, 02.12.2021 05:00 lpslover26237
Your answer should be in the form p(x) \dfrac{k}{x 1}p(x) x 1 k p, left parenthesis, x, right parenthesis, plus, start fraction, k, divided by, x, plus, 1, end fraction where ppp is a polynomial and kkk is an integer. \dfrac{x^2-2x-8}{x 1}= x 1 x 2 −2x−8 =start fraction, x, squared, minus, 2, x, minus, 8, divided by, x, plus, 1, end fraction, equals.
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Your answer should be in the form p(x) \dfrac{k}{x 1}p(x) x 1 k p, left parenthesis, x, right parent...
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