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Mathematics, 01.12.2021 19:00 9444

Is x βˆ’ 8 a factor of the function f(x) = βˆ’2x3 + 17x2 βˆ’ 64? Explain. Yes. When the function f(x) = βˆ’2x3 + 17x2 βˆ’ 64 is divided by x βˆ’ 8, the remainder is zero. Therefore, x βˆ’ 8 is a factor of f(x) = βˆ’2x3 + 17x2 βˆ’ 64.
No. When the function f(x) = βˆ’2x3 + 17x2 βˆ’ 64 is divided by x βˆ’ 8, the remainder is zero. Therefore, x βˆ’ 8 is not a factor of f(x) = βˆ’2x3 + 17x2 βˆ’ 64.
Yes. When the function f(x) = βˆ’2x3 + 17x2 βˆ’ 64 is divided by x βˆ’ 8, the remainder is not zero. Therefore, x βˆ’ 8 is a factor of f(x) = βˆ’2x3 + 17x2 βˆ’ 64.
No. When the function f(x) = βˆ’2x3 + 17x2 βˆ’ 64 is divided by x βˆ’ 8, the remainder is not zero. Therefore, x βˆ’ 8 is not a factor of f(x) = βˆ’2x3 + 17x2 βˆ’ 64.

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Is x βˆ’ 8 a factor of the function f(x) = βˆ’2x3 + 17x2 βˆ’ 64? Explain. Yes. When the function f(x) =...
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