What is the factorization of the expression below? 16x2 - 49
O A. (8x-7)(2x-7)
B. (8x + 7)(2x-7)
C. (4x+ 7)(4x-7)
D. (4x-7)(4x-7)
SUBMIT

16x² - 49

= (4x)² - 7²

Identity =》 a² - b² = (a + b) (a - b)

(4x)² - 7²

= (4x + 7) (4x - 7) [3rd option]

Hope it helps ⚜

Well factorizing 16x^2-49

You can use the difference of squares

Which is when theirs 2 perfect sqaures and it’s a subtraction problem.

So 16x^2 - 49

the formula is

a^2-b^2= (a+b) (a-b)

16x^2 - 7^2 = (a+b) (a-b)

SO plug it in

(4x+7) (4x-7)

Thats simplified to the max

So your answer would be (c)

s

step-by-step explanation:

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92