Find the equation of the normal to the circle, whose equation is given below, at the point (-4,4). (x + 2)^2 + (y - 3)^2 = 5
Give your answer in the form y = mx + c.

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!

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