An ice skating arena charges an admission fee for each child plus a rental fee for each pair of ice skates. John paid the admission fees for his 6 nephews and rented five pairs of ice skates. He was charged $32. Juanita paid admission fees for her seven grandchildren and rented 5 pairs of ice skates. She was charged $35.25. What is the admission fee?

What is the rental fee for a pair of skates?

if we let admission fee per child to be a and the rental fee for the skates  to be s.

Then john 6a + 5s =32

Juanita     7a + 5s = 35.25

Solving simultaneously we can eliminate s to solve for a first by subtracting one equation from the other.

        6a + 5s = 32

        7a + 5s = 35.25

we get -a + 0s = -3.25     therefore a= 3.25

Then we can solve for s by substituting a in either of the two equations

 6 (3.25) + 5s =32

 19.5 + 5s =32

            5s = 12.5

               s = 12.5/5

               s = 2.5

Therefore, the admission fee: $ 3.25 per person and rental fee: $ 2.5 per pair of skates.

Step-by-step explanation:

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form