An octopus weighed 3 5/6 kilograms. After two weeks, its weight was increased by 1 4/5 kilgrams. But afterwards, it got sick and lost 2 7/15 kilograms. what is the current weight?

14/15kg                  if its wrong plz correct me thank you.

Step-by-step explanation:

Rewriting our equation with parts separated

=1+215−15

Solving the fraction parts

2/15−15=?

Find the LCD of 2/15 and 1/5 and rewrite to solve with the equivalent fractions.

LCD = 15

2/15−3/15=−1/15

Combining the whole and fraction parts

1−1/15=14/15

Solution by Formulas

converting mixed numbers to fractions, our initial equation becomes,

17/15−15

Applying the fractions formula for subtraction,

=(17×5)−(1×15)15×5

=85−15/75

=70/75

Simplifying 70/75, the answer is

=14/15

I think it's 3 1/6 kilograms

Step-by-step explanation:

3 5/6 + 1 4/5 since it increased

find the LCD (Least Common Denominator)

that would be 30

3 25/30 + 1 24/30

=4 49/30

= 5 19/30

Then we do subtraction since it lost some weight

5 19/30 - 2 7/15

find LCD again

5 19/30 - 2 14/30

=3 5/30

simplify

3 1/6 kilograms. That's what I think.

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph

p

step-by-step explanation: