Quadrilateral JKLM with vertices J(2, 10), K(8,9), L(7,4), and M(3, 4):
J
k = 2, centered at (4,7)

Given:

Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10).

(a)If we translate  quadrilateral JKLM 3 units down and 3 units left:

(x-3,y-3), we obtain: W(5,1), X(1,7), Y(9,9), and Z(11,7)

Therefore, we match it with: A translation 3 units down and 3 units left

(b)If we translate  quadrilateral JKLM 2 units right and 3 units down:

(x+2,y-3), we obtain: O(10,1), P(6,7), Q(14,9), and R(16,7)

Therefore, we match it with:A translation 2 units right and 3 units down

S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

(c) If we transform quadrilateral JKLM by a sequence of reflections across the x- and y-axes, in any order, we obtain:

A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10)

(d)If we translate  quadrilateral JKLM 3 units left and 2 units up:

(x-3,y+2), we obtain:E(5,6), F(1,12), G(9,14), and H(11,12)

Therefore, we match it with: A translation 3 units left and 2 units up

(e)S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

No suitable transformation is found from JKLM to STUV.

Quadrilateral JKLM has vertices J(8, 4), K(4, 10), L(12, 12), and M(14, 10).

(a)If we translate quadrilateral JKLM 3 units down and 3 units left:

(x-3,y-3), we obtain: W(5,1), X(1,7), Y(9,9), and Z(11,7)

Therefore, we match it with: A translation 3 units down and 3 units left

(b)If we translate quadrilateral JKLM 2 units right and 3 units down:

(x+2,y-3), we obtain: O(10,1), P(6,7), Q(14,9), and R(16,7)

Therefore, we match it with:A translation 2 units right and 3 units down

S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

(c) If we transform quadrilateral JKLM by a sequence of reflections across the x- and y-axes, in any order, we obtain:

A(-8, -4), B(-4, -10), C(-12, -12), and D(-14, -10)

(d)If we translate quadrilateral JKLM 3 units left and 2 units up:

(x-3,y+2), we obtain:E(5,6), F(1,12), G(9,14), and H(11,12)

Therefore, we match it with: A translation 3 units left and 2 units up

(e)S(4, 16), T(10, 20), U(12, 12), and V(10, 10)

No suitable transformation is found from JKLM to STUV.

step-by-step explanation:

descending order means to order the polynomials from the term with the largest exponent to the term with the smallest exponent.  

therefore, the correct answer is d.