Find the value of 'y' if 27^y = 9/3^y.
Help me please..

y = 1/2.

Step-by-step explanation:

Note that 27 = 3^3 and 9 = 3^2:

27^y

= (3^3)^y

= 3^3y.

9/3^y

= 3^2/3^y

= 3^(2-y)

So 3^3y = 3^(2-y)

and therefore:

3y = 2 - y

4y = 2

y = 1/2.

Given that:

27^y = 9/3^y

⇛27^y × 3^y = 9

⇛(3^3)^y × 3^y = 9

⇛3^3y × 3^y = 9 [°.° (a^m)^n = a^mn]

⇛3^(3y+y) = 9 [°.° a^m×a^n = a^m+n]

⇛3^(4y) = 9

⇛3^(4y) = 3^2 [Bases equal ⇛exponents to equal]

.°. 4y = 2

y = 2:4 = 1/2

Hence, the value of y is 1/2.