The position vector of a particle of mass 0.05 kg is r (t) = 3 cos (4. t)i + 3 sin (4.t)j +10 t k What is the vector expression for the velocity of the particle at time t in m/s?
v (t) = ?

What is the vector expression for the acceleration of the particle at time t in m/s^2?
a(t) = ?

Deduce the magnitude of the force acting on the particle
|F| =

What is the direction of the acceleration compared with the velocity of the particle?

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.

jfkc

step-by-step explanation:

jhcxzbfzc

answer: i think its red because you have to see what it equals to

hope that