a rod 200cm long is broken into two parts. The sorter part is one quarter of the length of the rod. Express the shortest part as a percentage of the longer part

Length of a rod=200cm

Both parts of rod=?

Shortest part as percentage of longer part=?

Quarter of 200=200÷4

=50

Let the longer part be x

50+x=200

x=200-50

x=150

Hence, The values are:

Shortest part=50cm

Longest part=150cm

50 is 33.33% of 150

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)