What is an equation of the line that passes through the point (-1,-6) and is perpendicular to the line x+6y=6

Well x + 6y = 6 can be written 6y = -1x + 6 or y = (-1/6)x + 1. Any line perpendicular to this line will have a slope that is the multiplicative inverse of -1/6 which is +6

So the line passing through( -1,-6) having slope 6 is (y - -6) / (x - -1) = 6 or…………..(y + 6) / (x + 1) = 6 and multiplying both sides by x + 1 gives y+6 = 6(x + 1) and finally subtracting 6 we have y = 6(x+1) - 6 or y = 6x + 0.

This turns out to be a line that passes through the origin having slope 6/1

Step-by-step explanation:

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step-by-step explanation:

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