Image help | b), exercise 74 (this cost me 50 of my 53 points, please don't answer if you don't know)

x = 3Sides are 6, 8 and 10

Step-by-step explanation:

Use Pythagorean to find the value of x:

c² = a² + b²

Consider:

a = x + 3, b = 3x - 1, c = 4x - 2

Substitute and solve for x:

(4x - 2)²  = (x + 3)² + (3x - 1)²16x² - 16x + 4 = x² + 6x + 9 + 9x² - 6x + 116x² - 10x² - 16x + 4 - 10 = 06x² - 16x - 6 = 03x² - 8x - 3 = 03x² - 9x + x - 3 = 03x(x - 3) + (x - 3) = 0(x - 3)(3x + 1) = 0x - 3 = 0, 3x + 1 = 0x = 3, x = - 1/3

Positive root is accepted only.

Sides of the triangle:

a = x + 3 = 3 + 3 = 6b = 3x - 1 = 3*3 - 1 = 8c = 4x - 2 = 4*3 - 2 = 10

Yes, two vertical lines can be complementary