(I’m having trouble with this question, it would be greatly appreciated if I could have some help, thank you) What is the equation of a line that is parallel to – 2x + 3y = -6 and passes through the point (-2, 0)?

y = 2/3x + 4/3

Step-by-step explanation:

you need to know the slope of the line -2x + 3y = -6 because parallel lines have the same slopes

let's put the equation in y=mx+b format (slope-intercept format)

-2x + 3y = -6

add 2x to each side to get:

3y = 2x - 6

divide each side by 3 to get:

y = 2/3x - 2

the equation now shows us the slope is 2/3 and the y-intercept is (0,-2)

now we use y=mx+b again and use the point (-2,0) and the m=2/3 to get the y-intercept ('b' value) of the equation that is parallel:

0 = 2/3(-2) + b

0 = -4/3 + b

b = 4/3

equation would be:

y = 2/3x + 4/3

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.