4. A study conducted by an airline showed that a random sample of nine of its passengers disembarking at a certain airport took an average of 24.1 minutes to claim their luggage. From a previous survey it was willing to assume that time to claim luggage was normally distributed with a variance of 18 (minutes)2. Being 95% confident, what would be the margin of error in predicting the mean time to claim ones lu

a .4y4

hope this !

a; x = 0.5

step-by-step explanation:

-10x = -5

x = 0.5

median is the value separating the higher half of a data sample, a population or probablity distribution from the lower half.

step-by-step explanation:

say you have 3,8,7,3,1,9,8 order them from lowest to highest

if orderd it would be 1,3,3,7,8,8,9 now you take away from the lowest and the highest until you end up in the middle.

so you would remove the 1 and 9 leaving you with 5 digits remaining

when you've reached the middle that would be your answer so in this case the answer is 7

if there were two numbers left say 7 and 5 you'd and them together so 12 then divide by 2 witch would equal 6 so the answer would be 6

good luck on that project hoped i you at all

then say something, tell them they won’t respect you if you don’t even have respect for your self sweetheart you need to lay it on them, all of it : )