two busses left town A for town B at the same time the speed of the first bus was 10 mph greater than the second one. In 3 1/2 hours one buss was able o reach town B while the other one was still away from town B at a distance equal 1/6 oof the distancd between towns A and B. Find the speed of the busses and the distance between town A and town B

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

the answer is d

the answer is in the first quadrant, which make the y-int positive.

since the dots are going down, therefore the correlation is negative

i hope it is right.

the answer is 31.27mph

answer: i guess 5 units?

step-by-step explanation: