Write a quadratic function in standard form with axis of symmetry x=-5 and y -intercept 3 .

follow the statement below

Step-by-step explanation:

The question you presented here has multiple (un-limited) solutions unless you have another condition to solve for a single solution.

Equation: y = ax² + bx + c

y intercept (0 , 3): c = 3

axis of symmetry x=-5, therefore a corresponding point (-10,3) on the curve

3 = a*(-10)² + b*(-10) + 3

100a - 10b = 0

b = 10a  .... any pair like a=0.5 b=5; a=1 b=10 0r a=2 b=20 ..... all fit the function

y = 0.5x² + 5x +3

y = x² + 10x + 3

y = 2x² + 20x +3

........................

given that triangle abc is transformed two times to get triangle

a"b"c"

first abc is transformed in to a'b'c' as follows:

the coordinates of a are (1,-1) and transformed into a'(-1,1)

similarly b (4,-2) became b'(-4,2) and

c(7,-2) became c'(-7,2)

i.e. (x,y) becomes (-x,-y)

this is nothing but reflection about a point here origin.

thus first transformation is reflection on the origin.

next is exactly shifting 3 units down

source:

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step-by-step explanation:

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