What are the domain and range of f(x) = (one-sixth) Superscript x + 2? domain: Left-brace x vertical-line x greater-than negative one-sixth right-brace; range: {y | y > 0}
domain: Left-brace x vertical-line x greater-than one-sixth right-brace; range: {y | y > 2}
domain: {x | x is a real number}; range: {y | y > 2}
domain: {x | x is a real number}; range: {y | y > –2}

the answer is 4.8 units on e2020.

21

step-by-step explanation:

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.