If a total of 1100 square centimeters of material is to be used to make a box with a square base and an open top, find the largest possible volume of such a box.

Step-by-step explanation:

Let x = base side length

y = side height

volume V = x²y

y = V/x²

surface area

A = x² + 4xy

A = x² + 4x(V/x²)

A = x² + 4V/x

Solving for volume

V = (A - x²)(x/4)

V = ¼(Ax - x³)

a maximum will occur when the derivative equals zero

V' = ¼(A - 3x²)

0 = ¼(A - 3x²)

0 = A - 3x²

3x² = A

3x² = 1100

x² = (1100 / 3)

x = √(1100/3)

V = (A - x²)(x/4)

V = (1100 - √(1100/3))²(√(1100/3)/4)

V = 3,510.56606...

V = 3510.6 cm³

The box height will be half of the base side length.

y = ½√(1100/3)

the transverse axis of a hyperbola is the line that contains the two vertices and the two focuses.

in this example (hyperbola of equation x^2/2 - y^2/4 = 1), the transverse axis is the  x-axis  . 

step-by-step explanation:

after simplifying it i got: -36.25 as my answer. hope that !