Find an equation of a line parallel to the give line and contains the given point. Write the equation in slope-intercept form. line y=3x+4, point (2,5)

y=3x-1

Step-by-step explanation

y=mx+b

Since it is parallel, the slope (mx) would stay the same but would need to find another y-intercept (b).

1. Plug in the x and y and leave the y-intercept as a variable.

5=3(2)+b -> 5=6+b

2. Subtract the 6 to get it on the other side.

-1=b

So the y-intercept should be -1

3. Then you plug the slope and y-intercept back in the y=mx+b

So the answer should be y=3x-1 or y=3x+(-1)

Step-by-step explanation:

Method 2: Using Post Slope Form. What is the equation of line parallel to y = 3x + 5 and through the point (1, 7)?

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: