if f(x)=ax⁴+bx³-x²+2x+3 has a remainder when divided by (x-2)and has a remainder 2 when divided by x+1 find values of a and b

f(x)= ax^4+bx^3-x^2+2x+3

As per division concept

(3x+5)+(x^2-x-2)(g(x)= f(x)

g(x)=ax^2+bx--1

Coefficient of x in f(x) is +2

Coefficient of x in

3+1-2b=2

2b=2

b=1

73.0769230769% of the games were won

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)