Me podrian ayudar con estas equaciones de 2º grado pliss?
Thankss

Step-by-step explanation:

Las ecuaciones dadas son ,

=> x² + 2x -15 = 0

Y necesitamos encontrar la solución de la Ecuación dada.

=> x² + 5x -3x -15 = 0

=> x(x+5) -3(x+15) = 0

=> (x+5)(x-3) = 0

=> x = 3,-5

La segunda ecuación es,

=> x² -4x -12 = 0

=> x² -6x+2x-12=0

=> x(x-6)+2(x-6) = 0

=> (x+2)(x-6) = 0

=> x = 6,-2

Espero eso ayude :)

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

i believe the answers 600m