Put the following equation of a line into slope-intercept form, simplifying all fractions.
8x + 6y = -54

Step-by-step explanation:

The standard form of linear equation is: Ax + By = C, where A, B, and C are integers; A and B ≠ 0, and A is a non-negative integer.

Given the linear equation in standard form, 8x + 6y = -54, we can transform this equation into its slope-intercept form, y = mx + b.

First, subtract 8x from both sides:

8x + 6y = - 54

8x - 8x + 6y = - 8x - 54

6y = -8x  - 54

Divide both sides by 6 to isolate y:

⇒ This is the slope-intercept form where the slope, m = , and the y-intercept, b = -9.

1,918

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.