Farmer Ed has 9,500 meters of fencing, and wants to enclose a rectangular plot
that borders on a river. If Farmer Ed
does not fence the side along the river,
what is the largest area that can be
enclosed?
х
9,500 –2x

The largest area that can be enclosed is
square meters.
>

Because it is a rectangle, the area is expressed as A = xy, or length times width.

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get:

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get:

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for x

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equation

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distribute

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y

Because it is a rectangle, the area is expressed as A = xy, or length times width.Because it is next to the river, he only needs to fence three sides, so F = x + 2y.Knowing the amount of fencing available is 7500m, we get: 7500 = x + 2y solve for xx = 7500 - 2y substitute into the area equationA = (7500 - 2y)y distributeA = -2y2 +7500y You can see that this is a parabola which opens down, meaning that the point of maximum area will be at the vertex, y = - b/2a = -7500/[2(-2)] = 1875

/2a = -7500/[2(-2)] = 1875

/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750

/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750

/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2

/2a = -7500/[2(-2)] = 1875 x = 7500 - 2(1875) = 3750 A = 3750(1875) = 7,031,250 m2

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)