Solve the following quadratic equation by factorisation method 3 x square - 2 root 6 × + 2 =0

3x^2 -2root(6)x + 2 = 0

(root(3)x)^2 -2[root(3)x]root(2)+ (root(2))^2 = 0

let a = root(3)x and b = root(2)

a^2 -2ab + b^2 = 0

(a - b)^2 = 0

by the null factor rule,

a - b = 0

sub back in a and b

root(3)x = root(2)

x = root(3)/root(3)

Idon’t exactly understand but i think dbc=rst