The cost of admission to a festival was $112 for 9 children and 3 adults. The admission was $108 for 8 children and 3 adults in another festival. How much was the admission for each child and adult?

cost of admission for each child was $4.00, and each adult was $25.33

Step-by-step explanation:

When solving questions like these , I like to break down the problem so I understand it better.

Let x ---> cost of the admission for each child

Y > cost of the admission for each adult

9x+3y = 112 ---> equation A

8x + 3y = 108 ---> equation B

Subtract B from A

9x+3y=112

-8x+3y = 108

x = 112-108

x = 4

Find value of y by substituting value of x into equation

9(4)+3y=112

Solve for y

36+3y = 112

3y = 112=36

3y = 76

y = 25.33

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation:

3x^3-2x^2+4x-3= -3

x^2+3x+3= 3

-3÷3= -1