Uhh please help will give thingy

1. x=1

2. no solution

3. infinite solutions

Step-by-step explanation:

1. 2(x+3)=2x+5+x

2x+6=3x+5

6=x+5

1=x

2. 2(2x-3)=6x+2-2x-9

4x-6=6x+2-2x-9

4x-6=4x-7

-6=-7

-6 does not equal -7 so there is no solution

3. 4(2x+6)+2=2x+16+6x+10

8x+24+2=2x+16+6x+10

8x+26=8x+26

26=26

26 is equal to 26 so x could be equal to anything since it ends up cancelling itself out

steps I used to solve:

1. solve distributive property

2. combine like terms

3. add/subract from both sides to try and get x by itself

4. if x is by itself you have your answer, and if there isnt an x in the final answer there is no solution or infinite solutions.

just needed some points but try socratic