The temperature of a liquid in an experiment changes by −10.4°F from the beginning of the experiment to the first check. After making some adjustments, the scientist checks the temperature again later and finds that it is 17.7°F, which is 13 what it was at the time of the first check. What was the initial temperature of the liquid?

true? is that what you're asking or do you mean something else?

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°

i dont know

step-by-step explanation: