Consider rectangles with a height of 2 units. Increase their width by 1 unit at a time. What effect does this have on the total number of squares?What about rectangles with a height of 3 4 5 ?Make a note of the number of squares in rectangles with a height of 2 units. Do you notice anything special?

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graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

8(1/6)

step-by-step explain:

49/6= 48

8 (1/6)