(x+1)²+ (x-8)² = 0
in standard form and its roots

Step-by-step explanation:

what do you mean ? what needs to be done ?

solve the equation for x ?

(x+1)² + (x-8)² = 0

x² + 2x + 1 + x² -16x + 64 = 0

2x² - 14x + 65 = 0

the formula to solve such a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

a = 2

b = -14

c = 65

x = (14 ± sqrt(196 - 520))/4 = (14 ± sqrt(-324))/4 =

= (14 ± 18i)/4 = (7 ± 9i)/2

remember that the is no real solution to a square root of a negative number. sqrt(-1) is called I. and all numbers that are combinations with I are called complex numbers.

x1 = (7 + 9i)/2

x2 = (7 - 9i)/2

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)