A coordinate plane with a line passing through (negative 3, 0), (0, negative 2) and (3, negative 4). What is the equation of the graphed line written in standard form?

2x + 3y = –6
2x + 3y = 6
y equals negative StartFraction 2 Over 3 EndFraction x minus 2.
y equals StartFraction 2 Over 3 EndFraction x minus 2.

i think it will be zero as slope has a formula of difference between initial and final distance divided by itz time interval

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value

the image is given below

since the options are not given so we draw it from the equation

the given equation is

y = (x-1) (x+4)

y = y² + 3x - 4

the above equation is a quadratic equation which will have two roots. if we draw the graph for it, it will look like this

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation: