Please change to point-slope form :)) no work needed just a breif description on how I got the answers

Step-by-step explanation:

remember, the point slope form is

y - y1 = m(x - x1)

m is the slope.

x1 and y1 are the coordinates of the given point.

since the slope is always the factor of x and remains the same for parallel lines, you have m plainly described in every line equation, and you only need to copy it into the point slope form.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

the correct answer is 1: 2

step-by-step explanation:

hope this your welcome : )