Thirty randomly selected students took the calculus final. If the sample mean was 95 and the standard deviation was 6.6, construct a 99% confidence interval for the mean score of all students A: 91.68 < μ <98.32
B: 92.95 < μ < 97.05
C: 91.69 < μ < 98.31

A: 91.68 < μ <98.32

solution:

Sample standard error = 6.6/SQRT(30) = 1.205

t-value for the 99% CI = 2.756

Margin of error = 2.756 x 1.205 = 3.321

So, the 99% CI = (95 - 3.321 , 95 + 3.321) = (91.679 , 98.321)

you might have to contact customer support. if you have it on your iphone you just got into your settings> subscriptions> cancel

step-by-step explanation:

the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72