Help me solve please! To get to the camp in time, tourists had to go with a speed 4km/h. They went with that speed half of the road, but then they drove with a bus and arrived to the camp 2h 20min before the planned time. How many kilometers did tourists drive with the bus, if the speed of the bus was 60km/h?

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Step-by-step explanation:

This problem can be solved using distance formula;

s=vt

Here we suppose;

Speed of Tourists=v1=4 km/h

speed of bus=v2=60km/h

Total time to be taken by the tourists to reach the camp without bus=t

Time taken by tourists when bus used=t-2h20min=t-140min

let the total distance is ‘x’ but half is travelled without bus and other half by bus!

for first half distance=s1 =x/2

for second half distance=s2=x/2

Using s=vt formula for first half;

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step-by-step explanation:

b and c

see attached

step-by-step explanation:

given the function as;

write the equation replacing f(x) with y

form   and fill a table containing values of y with corresponding values of x

you can take a range for   values of x as -3≤x≤3

solving for x=-3

for x=-2

repeat the same procedure to get the values of y for the remaining ,x=-1 to x=3

plot the values of y against values   of x and obtain the following graph