the area of the rectangular city park is 25/24 square miles. the length of the park is 5/9 mile. what is the width, in mils, of the park

A rectangle's area is Length * Width [Let x = rectangle's width] A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) 25/54 = (5/9)x A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) 25/54 = (5/9)x (25/54)*(9/5) = x [multiply both sides by (9/5) A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) 25/54 = (5/9)x (25/54)*(9/5) = x [multiply both sides by (9/5) 5/6 = x [cancel out] A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) 25/54 = (5/9)x (25/54)*(9/5) = x [multiply both sides by (9/5) 5/6 = x [cancel out] A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) 25/54 = (5/9)x (25/54)*(9/5) = x [multiply both sides by (9/5) 5/6 = x [cancel out] The width is 5/6 miles A rectangle's area is Length * Width [Let x = rectangle's width] (25/54 square miles) = (5/9 miles)*(x miles) 25/54 = (5/9)x (25/54)*(9/5) = x [multiply both sides by (9/5) 5/6 = x [cancel out] The width is 5/6 miles Just to check: (5/9)*(5/6) = 25/54

You just need to add 32 to 14 and get 46.

The correct answer is c