What is a cubic polynomial function in standard form with zeros 3 –2 and 2 I really need help with this. At least just a nudge.

Thanks

x^3 - 3x^2 - 4x + 12

Step-by-step explanation:

Okay, so let's work backwards.

3, -2, 2 are the zeros, so we can use these numbers write the equation in factored form. (For right now, as a placeholder, I'll let y = 0)

(x - 3)(x + 2)(x - 2) = 0

If you want to check this, you can insert each of the zeros into the expression with a constant of the opposite sign.

So now, we can just expand the factored form. (I'll be doing this one equation at a time)

(x - 3)(x + 2) = x^2 + 2x - 3x - 6 = x^2 - x - 6

(x^2 - x - 6)(x - 2) = x^3 - 2x^2 - x^2 + 2x - 6x + 12 = x^3 - 3x^2 - 4x + 12

So,

The equation in standard form is x^3 - 3x^2 - 4x + 12

(Don't take my word for it though, now that I've told you how, feel free to do it on your own)

7.3

step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!