you roll a standard die. you win $12 if you roll a six, $6 if you roll a one, and $0 if you roll anything else. what is the expected value of a single roll?

$0

Step-by-step explanation:

      The chance of winning money is 2/6 -> 1/3, and sense 2/3 is larger than 1/3, we can conclude the expected value of a single roll is $0.

(I may be doing this problem wrong as I don't have context for what you're currently working on, but I hope this helps. Have a nice day!)

1 dollar

Step-by-step explanation:

Because if u roll a six it gives you six dollars so how many rolls you roll you get that amount of money. :)

I hope im right :D

this is false ^.^ lol

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %