The probability that a person in the United States has blue eyes is 27%. Four unrelated people in the United States are selected at random. a. Find the probability that all four have type blue eyes.
b. Find the probability that none of the four have blue eyes.
c. Find the probability that at least one of the four has blue eyes.
d. Find the probability that all four have brown eyes. Can this be done with this information?

l.jnl.j/n.m,lm,

step-by-step explanation:

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.

add them

step-by-step explanation:

idk you did not give the options or numbers so you cant solve it