Find the Area of the figure below, composed of a parallelogram and one semicircle. Rounded to the nearest tenths place

Hi,

Recall that the area of a parallelogram is the product of the base b and the height or "altitude" h. So the formula is : b * h. b = 20 here, and h = 6, so we get : 20 * 6 = 120.

Now we have to compute the area of the semicircle, remember the formula for the area of a circle is : πr² where r is the radius of the circle. If we watch the figure, we already have the value of the diameter d = 8. So the radius is equal to half the diameter : r = 8 /2 = 4

Now applying the formula we get : πr² = π * 4² ≈ 50.3 rounded to the nearest tenth place.

But we don't wont the area of the circle, we want half the area of it, since it's a semicircle : πr² / 2 ≈ 25.1 rounded to the nearest tenth place.

Now to get the whole area of the figure, we need to sum the area of the parallelogram with the area of the semicircle : 120 + 25.1 ≈ 145.1 rounded to the nearest tenth place.

Good Luck

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !