Solve for completing the square x^2-12x+11=0

x = 6 ± 5

Step-by-step explanation:

x² - 12x + 11 =0

x² - 12x = -11          Now add this number to both sides of the equal sign (1/2 of the coefficient of x-term squared)

x² - 12x +36 = -11 + 36                      1/2(-12)² = 36

(x - 6)(x - 6) = 25

(x - 6)² = 25

² =                             square root of both side of the equation

x - 6 =  ± 5                                          (5)² = 25 and (-5)² = 25

x = 6 ± 5

your answer would be 10x - 1

answer: i'm not sure

step-by-step explanation: