Mathematics, 24.10.2021 14:00 schnefai000
Rachna borrowed a certain sum at the rate of 15% per annum. if she paid at the end of the two years Rs.1290 as interest Compounded annually, find the sum she borrowed.
Answers: 3
![\quad{: \implies{\sf{C.I = \Bigg[P \bigg(1 + \dfrac{R}{100} \bigg)^{n} - 1 \Bigg]}}}](/tpl/images/2520/4235/f0708.png)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(1 + \dfrac{15}{100} \bigg)^{2} - 1 \Bigg]}}}](/tpl/images/2520/4235/7ebee.png)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{(1 \times 100) + 15}{100} \bigg)^{2} - 1 \Bigg]}}}](/tpl/images/2520/4235/e852b.png)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \bigg)^{2} - 1 \Bigg]}}}](/tpl/images/2520/4235/ce388.png)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{115}{100} \times \dfrac{115}{100} \bigg) - 1 \Bigg]}}}](/tpl/images/2520/4235/8af3a.png)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg(\dfrac{13225}{10000} \bigg) - 1 \Bigg]}}}](/tpl/images/2520/4235/1e526.png)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg( \cancel{\dfrac{13225}{10000}} \bigg) - 1 \Bigg]}}}](/tpl/images/2520/4235/fe326.png)
![\quad{: \implies{\sf{1290 = \Bigg[P \bigg({1.3225 - 1} \bigg) \Bigg]}}}](/tpl/images/2520/4235/cf612.png)
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Rachna borrowed a certain sum at the rate of 15% per annum. if she paid at the end of the two years...
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