What is the equation of the line that passes through the point(-5,-4) and has a slope of -3/5?

y= mx+c

-4= -3/5(-5) + c

-4= -3/5 *-5+ c

-4=3+c

-4-3=c

-7=c

therefore the equation of the line is y=-3/5x-7

Step-by-step explanation:

the equation of a line is

y=mx +c

where y is the y coordinate

where m is the slope

where x is the x coordinate

where c is the y- intercept

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

uhhh idk u yolo?