Which graph represents the equation y=-4/3x-2

Y = 3x2+ 4

When equation is in the form of y = Ax2 + Bx + C, it is in standard form.

A = 3, B = 0

Since A is positive, the graph opens upward.

Vertex is the lowest point on the graph.

The x coordinate of the vertex occurs at -B/2A

X =-B/2A = -0/2(3) = 0

To find the y-coordinate, we substitute 0 and solve for y

Y = 3(0)2 + 4 = 4

The vertex is at (0,4) ... the lowest point on the graph

From here, you can construct a table of values for x, and solve for y to obtain points on the graph.

Good x values to pick are -2, -1, 1, and 2

The domain is all the x-values for which the function is defined, The function is defined for all real values of x.

The domain is all real numbers. { x | x is a real number }

The range is all the y values obtained from input of the x-values.

The smallest y value is 4, the largest is positive infinity.

The range is all real numbers ≥ 4. { y | y ≥ 4 }

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v