Hello everyone , i am having some problems solving this question in maths
Arrange 13.25 kg, 14560 g, 13.6 kg, 12000 g in descending order ,
Write the following decimals as fractions. Reduce the fractions to lowest
form.
a) 3.6 b) 12.5
i hope u also consider explaining
thank you all .

Descending order:

14560g

13.6kg

13.25kg

12000g

a.)

b.)

Step-by-step explanation:

To find the difference between kg or g, either divide kg by 100 to convert to g, or multiply g by 1000 to convert to kg.

If we were to put everything into g:

14560g

13600g

13250g

12000g

See how they are still in the correct order?

If we were to put everything into kg:

14.56kg

13.6kg

13.25kg

12kg

Still in descending order!

___________________

Now to find out how to put the decimals into fractions:

Multiply by 10 (since there is only 1 digit behind the decimal, for every digit behind the decimal you multiply by another factor of 10, so if you have 2.55 you multiply by 100)

Following this we get:

36

125

Now divide by the same factor (10), we can't change the value of the number, just the way they look!

All that's left is it reduce!

And as you can see, we are back to the number I had put in the solution!

need more detail

step-by-step explanation:

lele

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.