The length of the field is 3 yards less than triple the width. What are the dimensions of the playing field

45=w answer

Step-by-step explanation:

Here's what we know:

P = 2L + 2w

L = 3w + 3 (length is 3 yards more than 3 times the length)

P = 366

We have a value for length and perimeter, so plug them in:

366 = 2(3w + 3) + 2w

366 = 6w + 6 + 2w

366 = 8w + 6

360 = 8w

45 = w

answer: 43/157

this is the answer and if you try to prove me wrong your a meanie

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option