Two lines in R3 are given by the vector equationsr1(t)= (t-6,2t,-3t+8c+21), r2(s)= (3s+2c, 4s+14, -6s)where t, s R, and c is a number. Find the value of c for which the two lines intersect each other, and find the point of intersection.

overpriced

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

false

step-by-step explanation:

false : it can not go to 9 the highest that part can go is 7

here is your proof