y=ax2+bx+c
Mathematics, 19.10.2021 14:00 2Pallie2
What is the stopping distance for a vehicle traveling at 20 mph?
QuadReg
y=ax2+bx+c
a=.0473809524
b= 2.221428571
C=-.005952381
R? =. 9999956228
o 20 ft
063.4ft
45.36 ft
126.4 ft
Ginish
Answers: 2
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What is the stopping distance for a vehicle traveling at 20 mph?
QuadReg
y=ax2+bx+c
y=ax2+bx+c
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